Q31 (SSC CGL 2025 – Time and Distance)
A car travels 180 km at 60 km/h. How long does it take?
- A. 2 hours
- B. 3 hours
- C. 4 hours
- D. 5 hours
Answer: B. 3 hours
Explanation: Time = Distance / Speed = 180 / 60 = 3 hours.
Q32 (IBPS PO 2025 – Profit and Loss)
An item’s CP is ₹800, sold at 15% profit. What is the SP?
- A. ₹900
- B. ₹920
- C. ₹940
- D. ₹960
Answer: B. ₹920
Explanation: SP = CP × (1 + Profit%) = 800 × 1.15 = ₹920.
Q33 (SBI Clerk 2025 – Compound Interest)
₹4,000 amounts to ₹4,840 in 2 years at CI. What is the rate?
- A. 8%
- B. 10%
- C. 12%
- D. 15%
Answer: B. 10%
Explanation: \( A = P (1 + R/100)^2 \), \( 4840 = 4000 \times (1 + R/100)^2 \), \( (1 + R/100)^2 = 1.21 \), \( R = 10\% \).
Q34 (RRB NTPC 2025 – Ratio)
Divide ₹1,000 in the ratio 2:3. What is the larger share?
- A. ₹500
- B. ₹600
- C. ₹700
- D. ₹800
Answer: B. ₹600
Explanation: Larger share = \( (3/(2+3)) \times 1000 = (3/5) \times 1000 = ₹600 \).
Q35 (LIC AAO 2025 – Percentages)
A number decreases by 10% to 90. What is the original number?
- A. 95
- B. 100
- C. 105
- D. 110
Answer: B. 100
Explanation: \( x \times 0.9 = 90 \), \( x = 90 / 0.9 = 100 \).
Q36 (SSC CGL 2025 – Time and Work)
6 workers complete a job in 10 days. How long will 8 workers take?
- A. 6 days
- B. 7 days
- C. 7.5 days
- D. 8 days
Answer: C. 7.5 days
Explanation: Work rate = \( 6/10 = 3/5 \). For 8 workers, time = \( 1 / (8 \times 1/10) = 10/8 = 7.5 \) days.
Q37 (IBPS PO 2025 – Simple Interest)
₹12,000 earns ₹3,600 in 3 years at SI. What is the rate?
- A. 8%
- B. 9%
- C. 10%
- D. 11%
Answer: C. 10%
Explanation: \( 3600 = (12000 \times R \times 3) / 100 \), \( R = 10\% \).
Q38 (SBI Clerk 2025 – Profit and Loss)
An item marked at ₹500 is sold at 20% discount. What is the SP?
- A. ₹380
- B. ₹400
- C. ₹420
- D. ₹440
Answer: B. ₹400
Explanation: SP = \( 500 \times 0.8 = 400 \).
Q39 (RRB NTPC 2025 – Time and Distance)
A train travels 300 km at 75 km/h. How long does it take?
- A. 3 hours
- B. 4 hours
- C. 5 hours
- D. 6 hours
Answer: B. 4 hours
Explanation: Time = \( 300 / 75 = 4 \) hours.
Q40 (LIC AAO 2025 – Ratio)
A and B’s incomes are in ratio 5:7. If A earns ₹25,000, what is B’s income?
- A. ₹30,000
- B. ₹32,000
- C. ₹35,000
- D. ₹40,000
Answer: C. ₹35,000
Explanation: \( (7/5) \times 25,000 = 35,000 \).
Q41 (CAT 2025 – Algebra)
Solve: \( 4x + 3 = 19 \).
- A. 3
- B. 4
- C. 5
- D. 6
Answer: B. 4
Explanation: \( 4x = 19 – 3 = 16 \), \( x = 16 / 4 = 4 \).
Q42 (UPSC CSAT 2025 – Quadratic Equations)
Solve: \( x^2 – 7x + 12 = 0 \).
- A. \( x = 3, 4 \)
- B. \( x = 2, 5 \)
- C. \( x = 1, 6 \)
- D. \( x = 4, 5 \)
Answer: A. \( x = 3, 4 \)
Explanation: \( (x – 3)(x – 4) = 0 \), so \( x = 3, 4 \).
Q43 (NDA 2025 – Polynomials)
What is the sum of roots of \( x^2 – 5x + 6 = 0 \)?
- A. 4
- B. 5
- C. 6
- D. 7
Answer: B. 5
Explanation: Sum of roots = \( -b/a = 5/1 = 5 \).
Q44 (CAT 2025 – Inequalities)
Solve: \( 2x – 5 > 3 \).
- A. \( x > 3 \)
- B. \( x > 4 \)
- C. \( x > 5 \)
- D. \( x > 6 \)
Answer: B. \( x > 4 \)
Explanation: \( 2x > 8 \), \( x > 4 \).
Q45 (UPSC CSAT 2025 – Linear Equations)
If \( x + y = 10 \) and \( x – y = 2 \), find \( x \).
- A. 4
- B. 5
- C. 6
- D. 7
Answer: C. 6
Explanation: Add equations: \( 2x = 12 \), \( x = 6 \).
Q46 (SSC CGL 2025 – Algebra)
Solve: \( 5x – 7 = 13 \).
- A. 3
- B. 4
- C. 5
- D. 6
Answer: B. 4
Explanation: \( 5x = 13 + 7 = 20 \), \( x = 20 / 5 = 4 \).
Q47 (IBPS PO 2025 – Quadratic Equations)
Solve: \( x^2 – 9x + 20 = 0 \).
- A. \( x = 4, 5 \)
- B. \( x = 3, 6 \)
- C. \( x = 2, 7 \)
- D. \( x = 1, 8 \)
Answer: A. \( x = 4, 5 \)
Explanation: \( (x – 4)(x – 5) = 0 \), so \( x = 4, 5 \).
Q48 (CAT 2025 – Polynomials)
Product of roots of \( x^2 – 4x + 3 = 0 \)?
- A. 1
- B. 2
- C. 3
- D. 4
Answer: C. 3
Explanation: Product of roots = \( c/a = 3/1 = 3 \).
Q49 (NDA 2025 – Inequalities)
Solve: \( 3x + 2 \leq 14 \).
- A. \( x \leq 3 \)
- B. \( x \leq 4 \)
- C. \( x \leq 5 \)
- D. \( x \leq 6 \)
Answer: B. \( x \leq 4 \)
Explanation: \( 3x \leq 14 – 2 = 12 \), \( x \leq 12 / 3 = 4 \).
Q50 (UPSC CSAT 2025 – Linear Equations)
If \( 2x + 3y = 12 \) and \( x + y = 5 \), find \( y \).
- A. 1
- B. 2
- C. 3
- D. 4
Answer: B. 2
Explanation: From \( x + y = 5 \), \( x = 5 – y \). Substitute: \( 2(5 – y) + 3y = 12 \), \( 10 – 2y + 3y = 12 \), \( y = 2 \).
Q51 (CDS 2025 – Geometry)
A triangle has sides 6, 8, 10 cm. What is its area?
- A. 20 cm²
- B. 24 cm²
- C. 28 cm²
- D. 32 cm²
Answer: B. 24 cm²
Explanation: Right triangle (6, 8, 10). Area = \( (1/2) \times 6 \times 8 = 24 \) cm².
Q52 (AFCAT 2025 – Circles)
A circle’s circumference is 88 cm. What is its area? (Use \( \pi = 22/7 \))
- A. 616 cm²
- B. 628 cm²
- C. 640 cm²
- D. 652 cm²
Answer: A. 616 cm²
Explanation: \( 2\pi r = 88 \), \( r = 88 \times 7 / (2 \times 22) = 14 \). Area = \( (22/7) \times 14^2 = 616 \) cm².
Q53 (JEE Main 2025 – Rectangles)
A rectangle’s area is 60 cm², length 15 cm. What is its perimeter?
- A. 32 cm
- B. 34 cm
- C. 36 cm
- D. 38 cm
Answer: B. 34 cm
Explanation: Breadth = \( 60 / 15 = 4 \) cm. Perimeter = \( 2(15 + 4) = 34 \) cm.
Q54 (CDS 2025 – Volume)
What is the volume of a cube with side 5 cm?
- A. 100 cm³
- B. 125 cm³
- C. 150 cm³
- D. 175 cm³
Answer: B. 125 cm³
Explanation: Volume = \( 5^3 = 125 \) cm³.
Q55 (AFCAT 2025 – Triangles)
A triangle’s angles are in ratio 2:3:4. What is the smallest angle?
- A. 20°
- B. 30°
- C. 40°
- D. 50°
Answer: C. 40°
Explanation: \( 2x + 3x + 4x = 180 \), \( 9x = 180 \), \( x = 20 \). Smallest angle = \( 2x = 40° \).
Q56 (SSC CGL 2025 – Mensuration)
A square’s perimeter is 48 cm. What is its area?
- A. 121 cm²
- B. 144 cm²
- C. 169 cm²
- D. 196 cm²
Answer: B. 144 cm²
Explanation: Side = \( 48 / 4 = 12 \) cm. Area = \( 12^2 = 144 \) cm².
Q57 (IBPS PO 2025 – Geometry)
A rectangle’s length is 10 cm, breadth 6 cm. What is its diagonal?
- A. 12 cm
- B. 14 cm
- C. 16 cm
- D. 18 cm
Answer: A. 12 cm
Explanation: Diagonal = \( \sqrt{10^2 + 6^2} = \sqrt{100 + 36} = \sqrt{136} = 12 \) cm.
Q58 (CAT 2025 – Circles)
A circle’s radius is 10 cm. What is its circumference? (Use \( \pi = 3.14 \))
- A. 62.8 cm
- B. 64.8 cm
- C. 66.8 cm
- D. 68.8 cm
Answer: A. 62.8 cm
Explanation: Circumference = \( 2 \times 3.14 \times 10 = 62.8 \) cm.
Q59 (NDA 2025 – Volume)
A cylinder’s radius is 7 cm, height 10 cm. What is its volume? (Use \( \pi = 22/7 \))
- A. 1540 cm³
- B. 1640 cm³
- C. 1740 cm³
- D. 1840 cm³
Answer: A. 1540 cm³
Explanation: Volume = \( \pi r^2 h = (22/7) \times 7^2 \times 10 = 1540 \) cm³.
Q60 (UPSC CSAT 2025 – Triangles)
A triangle’s base is 12 cm, height 8 cm. What is its area?
- A. 48 cm²
- B. 56 cm²
- C. 64 cm²
- D. 72 cm²
Answer: A. 48 cm²
Explanation: Area = \( (1/2) \times 12 \times 8 = 48 \) cm².
