Maths Objective Questions: Exponential & Logarithmic Functions
For UP TGT Exam Preparation
1. What is the value of e0?
Answer: B) 1
Explanation: Any non-zero number raised to the power of 0 is 1, so e0 = 1.
Explanation: Any non-zero number raised to the power of 0 is 1, so e0 = 1.
2. Simplify log10(100).
Answer: B) 2
Explanation: log10(100) = log10(102) = 2.
Explanation: log10(100) = log10(102) = 2.
3. What is the value of eln(x)?
Answer: A) x
Explanation: By the property of exponents and logarithms, eln(x) = x for x > 0.
Explanation: By the property of exponents and logarithms, eln(x) = x for x > 0.
4. Solve for x: log2(8) = x.
Answer: B) 3
Explanation: Since 8 = 23, log2(8) = log2(23) = 3.
Explanation: Since 8 = 23, log2(8) = log2(23) = 3.
5. What is the derivative of ex?
Answer: A) ex
Explanation: The derivative of ex with respect to x is ex.
Explanation: The derivative of ex with respect to x is ex.
6. Evaluate log4(64).
Answer: B) 3
Explanation: Since 64 = 43, log4(64) = log4(43) = 3.
Explanation: Since 64 = 43, log4(64) = log4(43) = 3.
7. Simplify log5(25).
Answer: B) 2
Explanation: Since 25 = 52, log5(25) = log5(52) = 2.
Explanation: Since 25 = 52, log5(25) = log5(52) = 2.
8. What is the value of 2log2(3)?
Answer: B) 3
Explanation: By properties of logarithms, 2log2(3) = 3.
Explanation: By properties of logarithms, 2log2(3) = 3.
9. What is the inverse of y = ex?
Answer: A) y = ln(x)
Explanation: The inverse of y = ex is y = ln(x), as ln(ex) = x.
Explanation: The inverse of y = ex is y = ln(x), as ln(ex) = x.
10. Solve: e2x = 5.
Answer: A) x = ln(5)/2
Explanation: Take ln of both sides: 2x = ln(5), so x = ln(5)/2.
Explanation: Take ln of both sides: 2x = ln(5), so x = ln(5)/2.
11. Simplify log3(81).
Answer: C) 4
Explanation: Since 81 = 34, log3(81) = log3(34) = 4.
Explanation: Since 81 = 34, log3(81) = log3(34) = 4.
12. What is log10(0.001)?
Answer: A) -3
Explanation: Since 0.001 = 10-3, log10(0.001) = log10(10-3) = -3.
Explanation: Since 0.001 = 10-3, log10(0.001) = log10(10-3) = -3.
13. Solve: 2x = 16.
Answer: C) 4
Explanation: Since 16 = 24, 2x = 24 implies x = 4.
Explanation: Since 16 = 24, 2x = 24 implies x = 4.
14. What is the domain of y = ln(x)?
Answer: A) x > 0
Explanation: The natural logarithm is defined only for positive values of x.
Explanation: The natural logarithm is defined only for positive values of x.
15. Simplify log2(1/8).
Answer: A) -3
Explanation: Since 1/8 = 2-3, log2(1/8) = log2(2-3) = -3.
Explanation: Since 1/8 = 2-3, log2(1/8) = log2(2-3) = -3.
16. What is the derivative of ln(x)?
Answer: A) 1/x
Explanation: The derivative of ln(x) with respect to x is 1/x.
Explanation: The derivative of ln(x) with respect to x is 1/x.
17. Solve: log5(x) = 2.
Answer: C) 25
Explanation: log5(x) = 2 implies x = 52 = 25.
Explanation: log5(x) = 2 implies x = 52 = 25.
18. Evaluate 3log3(5).
Answer: B) 5
Explanation: 3log3(5) = 5 by the inverse property of logarithms.
Explanation: 3log3(5) = 5 by the inverse property of logarithms.
19. What is the integral of ex dx?
Answer: A) ex + C
Explanation: The integral of ex is ex + C.
Explanation: The integral of ex is ex + C.
20. Simplify log10(1000).
Answer: B) 3
Explanation: Since 1000 = 103, log10(1000) = 3.
Explanation: Since 1000 = 103, log10(1000) = 3.
21. Solve: ex = 10.
Answer: A) ln(10)
Explanation: Take ln of both sides: x = ln(10).
Explanation: Take ln of both sides: x = ln(10).
22. What is the range of y = ex?
Answer: B) y > 0
Explanation: The exponential function ex is always positive for all real x.
Explanation: The exponential function ex is always positive for all real x.
23. Simplify log2(16x).
Answer: A) 4 + log2(x)
Explanation: log2(16x) = log2(16) + log2(x) = log2(24) + log2(x) = 4 + log2(x).
Explanation: log2(16x) = log2(16) + log2(x) = log2(24) + log2(x) = 4 + log2(x).
24. Solve: log3(x) + log3(x-2) = 1.
Answer: A) 3
Explanation: log3(x(x-2)) = 1, so x(x-2) = 31 = 3. Solve x2 – 2x – 3 = 0, x = 3 (x = -1 invalid).
Explanation: log3(x(x-2)) = 1, so x(x-2) = 31 = 3. Solve x2 – 2x – 3 = 0, x = 3 (x = -1 invalid).
25. What is the value of log10(1)?
Answer: A) 0
Explanation: log10(1) = 0, as 100 = 1.
Explanation: log10(1) = 0, as 100 = 1.
26. What is the integral of 1/x dx?
Answer: A) ln|x| + C
Explanation: The integral of 1/x is ln|x| + C.
Explanation: The integral of 1/x is ln|x| + C.
27. Solve: 4x = 64.
Answer: B) 3
Explanation: Since 64 = 43, 4x = 43 implies x = 3.
Explanation: Since 64 = 43, 4x = 43 implies x = 3.
28. Simplify log5(x2).
Answer: A) 2 log5(x)
Explanation: log5(x2) = 2 log5(x) by the power rule.
Explanation: log5(x2) = 2 log5(x) by the power rule.
29. What is the value of eln(2)?
Answer: B) 2
Explanation: eln(2) = 2 by the inverse property.
Explanation: eln(2) = 2 by the inverse property.
30. Solve: log2(x+1) = 3.
Answer: A) 7
Explanation: log2(x+1) = 3 implies x+1 = 23 = 8, so x = 7.
Explanation: log2(x+1) = 3 implies x+1 = 23 = 8, so x = 7.
31. What is the base of the natural logarithm?
Answer: B) e
Explanation: The natural logarithm has base e ≈ 2.718.
Explanation: The natural logarithm has base e ≈ 2.718.
32. Simplify log10(x/100).
Answer: A) log10(x) – 2
Explanation: log10(x/100) = log10(x) – log10(100) = log10(x) – 2.
Explanation: log10(x/100) = log10(x) – log10(100) = log10(x) – 2.
33. Solve: 52x = 25.
Answer: A) 1
Explanation: Since 25 = 52, 52x = 52 implies 2x = 2, so x = 1.
Explanation: Since 25 = 52, 52x = 52 implies 2x = 2, so x = 1.
34. What is the derivative of 2x?
Answer: A) 2x ln(2)
Explanation: The derivative of ax is ax ln(a), so for 2x, it’s 2x ln(2).
Explanation: The derivative of ax is ax ln(a), so for 2x, it’s 2x ln(2).
35. Evaluate log3(1/27).
Answer: A) -3
Explanation: Since 1/27 = 3-3, log3(1/27) = log3(3-3) = -3.
Explanation: Since 1/27 = 3-3, log3(1/27) = log3(3-3) = -3.
36. Solve: ln(x) = 0.
Answer: B) 1
Explanation: ln(x) = 0 implies x = e0 = 1.
Explanation: ln(x) = 0 implies x = e0 = 1.
37. What is the value of log10(105)?
Answer: C) 5
Explanation: log10(105) = 5 by the definition of logarithms.
Explanation: log10(105) = 5 by the definition of logarithms.
38. Simplify e2ln(x).
Answer: B) x2
Explanation: e2ln(x) = (eln(x))2 = x2.
Explanation: e2ln(x) = (eln(x))2 = x2.
39. Solve: 3x+1 = 27.
Answer: B) 2
Explanation: Since 27 = 33, 3x+1 = 33 implies x+1 = 3, so x = 2.
Explanation: Since 27 = 33, 3x+1 = 33 implies x+1 = 3, so x = 2.
40. What is the derivative of x ln(x)?
Answer: C) 1/x + ln(x)
Explanation: Using the product rule, d/dx[x ln(x)] = ln(x) + x(1/x) = ln(x) + 1.
Explanation: Using the product rule, d/dx[x ln(x)] = ln(x) + x(1/x) = ln(x) + 1.
41. Evaluate log2(32).
Answer: C) 5
Explanation: Since 32 = 25, log2(32) = 5.
Explanation: Since 32 = 25, log2(32) = 5.
42. Solve: e3x = e6.
Answer: B) 2
Explanation: e3x = e6 implies 3x = 6, so x = 2.
Explanation: e3x = e6 implies 3x = 6, so x = 2.
47. What is the base of the common logarithm?
Answer: C) 10
Explanation: The common logarithm, denoted log(x), has a base of 10.
Explanation: The common logarithm, denoted log(x), has a base of 10.
48. Simplify log2(8x3).
Answer: A) 3 + 3log2(x)
Explanation: log2(8x3) = log2(8) + log2(x3) = log2(23) + 3log2(x) = 3 + 3log2(x).
Explanation: log2(8x3) = log2(8) + log2(x3) = log2(23) + 3log2(x) = 3 + 3log2(x).
49. Solve for x: log5(x) + log5(x + 4) = 1.
Answer: A) 1
Explanation: log5(x(x + 4)) = 1, so x(x + 4) = 5. Solving x2 + 4x – 5 = 0 gives x = 1 (x = -5 is invalid).
Explanation: log5(x(x + 4)) = 1, so x(x + 4) = 5. Solving x2 + 4x – 5 = 0 gives x = 1 (x = -5 is invalid).
50. What is the value of log3(9) + log3(27)?
Answer: C) 5
Explanation: log3(9) = log3(32) = 2, log3(27) = log3(33) = 3, so 2 + 3 = 5.
Explanation: log3(9) = log3(32) = 2, log3(27) = log3(33) = 3, so 2 + 3 = 5.
